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Ranks and integer points on elliptic curves induced by Fibonacci triples

Andrej Dujella

Source record

Source: arXiv

Published: Sep 1, 2026

arXiv: 2609.01789

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Source abstract

Let FnF_n and LnL_n denote the Fibonacci and Lucas numbers, respectively, and consider Ek:y2=(F2kx+1)(F2k+2x+1)(F2k+4x+1). E_k:\qquad y^2=(F_{2k}x+1)(F_{2k+2}x+1)(F_{2k+4}x+1). These elliptic curves arise naturally from the regular Diophantine triples {F2k,F2k+2,F2k+4}. \{F_{2k},F_{2k+2},F_{2k+4}\}. For odd kk, we exhibit the rational point Qk=(Fk1LkFk+1Fk+2,F2k+1LkFk+1Fk+2). Q_k=\left( -\frac{F_{k-1}}{L_kF_{k+1}F_{k+2}}, \frac{F_{2k+1}}{L_kF_{k+1}F_{k+2}} \right). For every odd k3k\geq 3, this point is independent of the standard point Pk=(0,1)P_k=(0,1); in particular, rankEk(Q)2\operatorname{rank}E_k(\mathbb{Q})\geq 2. Moreover, if k3k\geq 3 is odd and rankEk(Q)=2\operatorname{rank}E_k(\mathbb{Q})=2, then all integer points on EkE_k are exactly the points arising from the two known solutions of the Hoggatt-Bergum extension problem. By parametrizing the two conics L25F2=±4L^2-5F^2=\pm4 and applying an injective specialization criterion, we also show that the corresponding one-parameter elliptic families have generic ranks 22 in the odd case and 11 in the even case. Finally, we discuss computational data and propose the heuristic rank distribution 1/4,1/2,1/41/4,1/2,1/4 for ranks 1,2,31,2,3, respectively, with density zero for rank at least 44.

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