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Forbidden Subgraphs Generating Almost the Same Sets

SHINYA FUJITA, MICHITAKA FURUYA, KENTA OZEKI

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Source: Crossref

Published: Jul 11, 2013

DOI: 10.1017/s0963548313000254

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Source abstract

Let H\mathcal{H} be a set of connected graphs. A graph G is said to be H\mathcal{H} -free if G does not contain any element of H\mathcal{H} as an induced subgraph. Let Fk(H)\mathcal{F}_{k}(\mathcal{H}) be the set of k -connected H\mathcal{H} -free graphs. When we study the relationship between forbidden subgraphs and a certain graph property, we often allow a finite exceptional set of graphs. But if the symmetric difference of Fk(H1)\mathcal{F}_{k}(\mathcal{H}_{1}) and Fk(H2)\mathcal{F}_{k}(\mathcal{H}_{2}) is finite and we allow a finite number of exceptions, no graph property can distinguish them. Motivated by this observation, we study when we obtain a finite symmetric difference. In this paper, our main aim is the following. If ∣H∣≤3|\mathcal{H}|\leq 3 and the symmetric difference of F1({H})\mathcal{F}_{1}(\{H\}) and F1(H)\mathcal{F}_{1}(\mathcal{H}) is finite, then either H∈HH\in \mathcal{H} or ∣H∣=3|\mathcal{H}|=3 and H = C 3 . Furthermore, we prove that if the symmetric difference of Fk({H1})\mathcal{F}_{k}(\{H_{1}\}) and Fk({H2})\mathcal{F}_{k}(\{H_{2}\}) is finite, then H 1 = H 2 .

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