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Infinitely Many Off-Critical-Line Zeros of the Tempered Xi Function: A Disproof of Yang's Conjecture

Aiken Kazin, Shirali Kadyrov

Source record

Source: arXiv

Published: Sep 24, 2026

arXiv: 2609.29898

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Source abstract

Yang introduced a tempered xi function ξ^(s)\widehatξ(s) by replacing the hyperbolic cosine in a classical integral representation of the Riemann xi function by a hyperbolic sine, and conjectured that every zero of ξ^\widehatξ lies on the critical line ℜs=1/2\Re s=1/2. We disprove this conjecture. After the change of variables x=e2tx=e^{2t}, one has ξ^ ⁣(12+iz)=iS(z),S(z)=∫0∞K(t)sin⁡(zt) dt, \widehatξ\!\left(\tfrac12+iz\right)=iS(z), \qquad S(z)=\int_0^\infty K(t)\sin(zt)\,dt, where KK is positive, smooth, and doubly exponentially decaying. Two integrations by parts give S(y)=K(0)/y+O(y−2)S(y)=K(0)/y+O(y^{-2}) for real ∣y∣→∞|y|\to\infty, with K(0)>0K(0)>0; hence SS has only finitely many real zeros. On the other hand SS is an entire function of order at most one. If it had only finitely many zeros in the complex plane, Hadamard factorization would force S(z)=P(z)eaz+bS(z)=P(z)e^{az+b}, which is incompatible with S(y)→0S(y)\to0 as y→±∞y\to\pm\infty. Thus SS has infinitely many nonreal zeros, and consequently ξ^\widehatξ has infinitely many zeros off the critical line. The proof is unconditional and does not use the Riemann Hypothesis or numerical zero finding. A short numerical illustration is included.

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