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The method of telescoping continued fractions

Gaurav Bhatnagar, Krishnan Rajkumar

Source record

Source: arXiv

Published: Sep 7, 2026

arXiv: 2609.07092

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Source abstract

We give an approach to discover continued fractions for series of the form k=0εk(x+k)s,\sum_{k=0}^\infty \frac{ε^k}{(x+k)^s}, where ε=±1ε= \pm 1. We find a continued fraction of the form \begin{equation*} \frac{a_1}{b_1(x)} \fplus \frac{a_2}{b_2(x)} \fplus \fdots \end{equation*} where aka_k are constants and bk(x)b_k(x) are polynomials. Our technique involves telescoping continued fractions. This provides a discovery approach to continued fractions given by Ramanujan for 2k=1(1)k+1x+2k1,2k=01(x+2k+1)2,2k=0(1)k(x+2k+1)2,k=11(x+k)3,2\sum_{k=1}^\infty \frac{(-1)^{k+1}}{x+2k-1}, 2\sum_{k=0}^\infty \frac{1}{(x+2k+1)^2}, 2\sum_{k=0}^\infty \frac{(-1)^k}{(x+2k+1)^2}, \sum_{k=1}^\infty \frac{1}{(x+k)^3}, and the like. We display the first few terms of several continued fractions obtained in this manner for larger values of ss, including s=5,7,9,11s=5, 7, 9, 11. They do not follow as simple a pattern as Ramanujan's continued fractions.

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