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Optimal thresholds for monotone non-Boolean functions

Saba Lepsveridze, Allen Lin

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Source: Crossref

Published: Jul 21, 2026

DOI: 10.1017/s0963548326100510

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Abstract Let left bracket q right bracket equals StartSet 0 comma 1 comma ellipsis comma q minus 1 EndSet [ q ] = { 0 , 1 , … , q − 1 } [q]={0,1,…,q−1}[q] = \{0,1,\ldots ,q-1\} , let normal upper Delta left bracket q right bracket Δ [ q ] Δ[q]\Delta [q] denote the simplex of probability measures on left bracket q right bracket [ q ] [q][q] , and let gamma γ γ\gamma denote the Lebesgue measure normalized on normal upper Delta left bracket q right bracket Δ [ q ] Δ[q]\Delta [q] . We prove that for any symmetric monotone function f colon left bracket q right bracket Superscript n Baseline right arrow left bracket q right bracket f : [ q ] n → [ q ] f ⁣:[q]n→[q]{\kern1pt}f \colon{\kern-1pt} [q]^n \to [q] and any a element of left bracket q right bracket a ∈ [ q ] a∈[q]a \in [q] , we have γ ( { μ ∈ Δ [ q ] | P x ∼ μ ⊗ n [ f ( x ) = a ] ∈ ( ε , 1 − ε ) } ) = O ( 1 / log ⁡ n ) . γ({μ∈Δ[q]  ∣  Px∼μ⊗n[ f(x)=a]∈(ε,1−ε)})=O(1/log⁡n).\begin{equation*} \gamma (\{\mu \in \Delta [q]\;\vert \;\mathbb{P}_{x\sim \mu ^{\otimes n}}[\,f(x)=a] \in (\varepsilon ,1-\varepsilon )\}) = O(1/\log n)\text{.} \end{equation*} We also show that this bound is tight. This improves Kalai and Mossel's previous bound of upper O left parenthesis log log n slash log n right parenthesis O ( log ⁡ log ⁡ n / log ⁡ n ) O( ⁣log⁡log⁡n/log⁡n)O(\!\log \log n/\log n) and answers their question completely.

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Optimal thresholds for monotone non-Boolean functions — Mathematical Frontier Network