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A Proof of the Riemann Hypothesis Based on a New Expression of the Completed Zeta Function

Weicun Zhang

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Source: Crossref

Published: Dec 21, 2021

DOI: 10.20944/preprints202108.0146.v14

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Source abstract

The completed zeta function ξ(s)\xi(s) is expanded in MacLaurin series (infinite polynomial), which can be further expressed as infinite product (Hadamard product) of quadratic factors by its complex conjugate zeros αi±jβi,βi0,iN\alpha_i\pm j\beta_i, \beta_i\neq 0, i\in \mathbb{N} are natural numbers, from 11 to infinity, N\mathbb{N} is the set of natural numbers. Then, according to the functional equation ξ(s)=ξ(1s)\xi(s)=\xi(1-s), we have ξ(0)i=1βi2αi2+βi2(1+(sαi)2βi2)=ξ(0)i=1βi2αi2+βi2(1+(1sαi)2βi2)\xi(0)\prod_{i=1}^{\infty}\frac{\beta_i^2}{\alpha_i^2+\beta_i^2}\Big{(}1+\frac{(s-\alpha_i)^2}{\beta_i^2}\Big{)} =\xi(0)\prod_{i=1}^{\infty}\frac{\beta_i^2}{\alpha_i^2+\beta_i^2}\Big{(}1+\frac{(1-s-\alpha_i)^2}{\beta_i^2}\Big{)} which, by Lemma 3 and Corollary 1, is equivalent to (sαi)2=(1sαi)2,iN(s-\alpha_i)^2 = (1-s-\alpha_i)^2, i \in \mathbb{N} with solution αi=12,iN\alpha_i= \frac{1}{2}, i\in \mathbb{N} (another solution s=12s=\frac{1}{2} is invalid due to obvious contradiction). Thus, a proof of the Riemann Hypothesis is achieved.

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