The factorization of the ninth Fermat number

Source abstract

In this paper we exhibit the full prime factorization of the ninth Fermat number F 9 = 2 512 + 1 {F_9} = {2^{512}} + 1 . It is the product of three prime factors that have 7, 49, and 99 decimal digits. We found the two largest prime factors by means of the number field sieve, which is a factoring algorithm that depends on arithmetic in an algebraic number field. In the present case, the number field used was Q ( 2 5 ) {\mathbf {Q}}(\sqrt [5]{2}) . The calculations were done on approximately 700 workstations scattered around the world, and in one of the final stages a supercomputer was used. The entire factorization took four months.