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Finite-order exponential mixing does not imply the central limit theorem

Bernat Bassols Cornudella, Matheus M Castro

Source record

Source: arXiv

Published: Oct 12, 2026

arXiv: 2610.17162

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Source abstract

We show that finite-order exponential mixing does not imply the central limit theorem for smooth diffeomorphisms. For every integer R≥2R\geq2, we construct a C∞\mathcal{C}^{\infty} diffeomorphism T:M→MT:M\to M of a compact smooth manifold MM and a TT-invariant probability measure μμ such that (T,μ)(T,μ) is exponentially mixing of order RR for C1(M)\mathcal{C}^1(M) observables, but not of order 2R+22R+2. For some centred observable f0∈C∞(M)f_0\in\mathcal{C}^{\infty}(M), no subsequence of the normalised sums 1n∑i=0n−1f0∘Ti\frac{1}{\sqrt n}\sum_{i=0}^{n-1}f_0\circ T^i converges in distribution to a Gaussian law. In particular, exponential decay of two-point correlations implies neither exponential mixing of all orders nor the central limit theorem. We realise (T,μ)(T,μ) in two ways. In the first, TT is a fixed linear Anosov diffeomorphism of T2\mathbb T^2 and μμ is singular with respect to Lebesgue measure. In the second, MM can be any compact smooth surface without boundary and μμ is a physical measure whose statistical basin contains a nonempty open set. The main theorems have been formalised in Lean 4.

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Finite-order exponential mixing does not imply the central limit theorem — Mathematical Frontier Network