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Equality Cases in the Tu-Deng Conjecture Bound

Thomas W. Cusick

Source record

Source: arXiv

Published: Oct 8, 2026

arXiv: 2610.12630

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Source abstract

The Tu-Deng Conjecture, made in 2011, asserts that for k≥2k\geq2 and 1≤t<2k−11\leq t<2^k-1, the set \[ S_{t,k}=\left\{(a,b)\in\{0,1,\ldots,2^k-2\}^2: a+b\equiv t\pmod{2^k-1},\quad \wt(a)+\wt(b)<k\right\} \] satisfies ∣St,k∣≤2k−1. |S_{t,k}|\leq 2^{k-1}. Proofs of the conjecture were given independently by the author and by Liu, Luo and Xie in arXiv in 2026. Let $r=\wt(t)$, and let z=k−rz=k-r be the number of zeros in the kk-bit expansion of tt. We prove that equality holds in the Tu-Deng Conjecture if and only if every cyclic distance between consecutive zeros is at least zz. We give several other simple necessary and sufficient conditions, including a forbidden-pattern condition, a packing condition for the zero positions, a composition condition for the gaps, and equivalent conditions involving the coefficients of the polynomial HW(u,v)H_W(u,v) in the proof of the Tu-Deng conjecture. We also count the equality words having a prescribed number of zeros.

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Equality Cases in the Tu-Deng Conjecture Bound — Mathematical Frontier Network