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A Survey of Forbidden Configuration Results

Richard Anstee

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Source: Crossref

Published: Jan 29, 2013

DOI: 10.37236/2379

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Source abstract

Let FF be a k×ℓk\times \ell (0,1)-matrix. We say a (0,1)-matrix AA has FF as a configuration if there is a submatrix of AA which is a row and column permutation of FF. In the language of sets, a configuration is a trace and in the language of hypergraphs a configuration is a subhypergraph.Let FF be a given k×ℓk\times \ell (0,1)-matrix. We define a matrix to be simple if it is a (0,1)-matrix with no repeated columns. The matrix FF need not be simple. We define forb(m,F)\hbox{forb}(m,F) as the maximum number of columns of any simple mm-rowed matrix AA which do not contain FF as a configuration. Thus if AA is an m×nm\times n simple matrix which has no submatrix which is a row and column permutation of FF then n≤forb(m,F)n\le\hbox{forb}(m,F). Or alternatively if AA is an m×(forb(m,F)+1)m\times (\hbox{forb}(m,F)+1) simple matrix then AA has a submatrix which is a row and column permutation of FF. We call FF a forbidden configuration. The fundamental result is due to Sauer, Perles and Shelah, Vapnik and Chervonenkis. For KkK_k denoting the k×2kk\times 2^k submatrix of all (0,1)-columns on kk rows, then forb(m,Kk)=(mk−1)+(mk−2)+⋯(m0)\hbox{forb}(m,K_k)=\binom{m}{k-1}+\binom{m}{k-2}+\cdots \binom{m}{0}. We seek asymptotic results for forb(m,F)\hbox{forb}(m,F) for a fixed FF and as mm tends to infinity . A conjecture of Anstee and Sali predicts the asymptotically best constructions from which to derive the asymptotics of forb(m,F)\hbox{forb}(m,F). The conjecture has helped guide the research and has been verified for k×ℓk\times \ell FF with k=1,2,3k=1,2,3 and for simple FF with k=4k=4 as well as other cases including ℓ=1,2\ell=1,2. We also seek exact values for forb(m,F)\hbox{forb}(m,F).

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