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Why Distance Two Is Exceptional for Poisson-Binomial Point Probabilities

Igor Kleiner

Source record

Source: arXiv

Published: Oct 7, 2026

arXiv: 2610.10664

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Source abstract

Let SS be a finite sum of independent Bernoulli random variables. We ask how large the mean must be before the atom at k+rk+r can strictly exceed the atom at kk. For the threshold Tk,r:=inf⁡{ES:P(S=k+r)>P(S=k)}T_{k,r}:=\inf\{\mathbb{E}S:\mathbb{P}(S=k+r)>\mathbb{P}(S=k)\}, the adjacent case recovers the classical Darroch boundary k+1/(k+2)k+1/(k+2), while every gap r≥3r\ge3 has threshold k+1k+1. Distance two is the unique nonadjacent exception: Tk,2=k+ΔkT_{k,2}=k+Δ_k, where ΔkΔ_k and its staircase optimizer are explicit and Δk=1/2+1/2k−1/(4k)+O(k−3/2)Δ_k=1/2+1/\sqrt{2k}-1/(4k)+O(k^{-3/2}). The proof combines the classical fixed-mean reduction to shifted binomial laws with an exact discrete optimization. The result also yields sharp restrictions on nonadjacent coefficient reversals in real-rooted polynomials with nonnegative coefficients.

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Why Distance Two Is Exceptional for Poisson-Binomial Point Probabilities — Mathematical Frontier Network