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Generating and generalizing MSTD sets through Markov processes

Frank He, Karol Daniewski, Steven J. Miller

Source record

Source: arXiv

Published: Oct 6, 2026

arXiv: 2610.08394

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Source abstract

The classical More Sums Than Differences (MSTD) problem studies finite sets A⊂{0,1,…,n}A\subset\{0,1,\ldots,n\} for which ∣A+A∣>∣A−A∣|A+A|>|A-A|, where A+A={a1+a2:a1,a2∈A}A+A=\{a_1+a_2:a_1,a_2\in A\} and A−A={a1−a2:a1,a2∈A}A-A=\{a_1-a_2:a_1,a_2\in A\}. As addition is commutative and subtraction is not, it was conjectured that as n→∞n\to\infty almost all subsets AA chosen uniformly from the power set of {0,1,…,n}\{0,1,\ldots,n\} are difference-dominated, and it was thus a surprise when Martin and O'Bryant proved a positive percentage of sets are sum-dominant. We greatly generalize this model by introducing a Markov-chain framework, where the classical MSTD model is now just a special case. Let (Xi)i=0n(X_i)_{i=0}^n be a stationary two-state Markov chain on {0,1}\{0,1\} with transition probabilities P(0,0)=pP(0,0)=p and P(1,1)=qP(1,1)=q, where p,q∈(0,1)p,q\in(0,1). We include ii in AA exactly when Xi=1X_i=1, and define A={i∈{0,…,n}:Xi=1}A=\{i\in\{0,\ldots,n\}:X_i=1\}. The usual independent Bernoulli model is recovered when consecutive inclusion decisions are independent, equivalently when p=1−qp=1-q. In particular, the uniformly random subset model corresponds to p=q=1/2p=q=1/2. Using the fringe-middle method from the MSTD literature, we show that the middle sums and differences are filled with high probability, so the comparison between ∣A+A∣|A+A| and ∣A−A∣|A-A| is again governed by endpoint fringes. By fringe manipulation, we prove that the probabilities of sum-dominant, difference-dominant, and balanced sets tend to strictly positive limits as n→∞n\to\infty. We also give numerical estimates of these three probabilities for finite nn over a range of values of pp and qq. Through combinatorial methods, we find a closed-form expression for E[∣A−A∣−∣A+A∣]\mathbb{E}[|A-A|-|A+A|] as n→∞n\to\infty.

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