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Schottky versus super Schottky in genus 4

Ron Donagi, Simone Noja

Source record

Source: arXiv

Published: Sep 14, 2026

arXiv: 2609.16131

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Source abstract

The study of super Riemann surfaces and their moduli led Witten and Felder, Kazhdan and Polishchuk to ask what is the smallest dd such that the dd-th power of the Schottky ideal is contained in the super Schottky ideal. Felder, Kazhdan and Polishchuk proved that d=gd=g in odd genus g5g\geq5 and that d{g1,g}d\in\{g-1,g\} in even genus g4g\geq4; Y.~Shen subsequently proved that d=gd=g in even genus g6g\geq6. Thus the only remaining open case was g=4g=4. Here we close this gap by showing that in genus 44 too, the smallest power of the Schottky ideal contained in the super Schottky ideal is d=g=4d=g=4. The question is equivalent to one concerning the codifferential of the super period map. The quadratic odd contribution sends a conormal vector to a bivector, represented by a skew-symmetric (2g2)×(2g2)(2g-2)\times(2g-2) matrix. The question is to find such a vector for which, at a generic point, this matrix has maximal rank 2g22g-2, or 66 in our case. Our computation uses the standard exact sequences on C×CC\times C attached to the sheaves $\OO(a,b,c)$, together with a degeneration to a vanishing theta-null and some facts about the Szegő kernel. At a curve with a vanishing theta-null, a regularized version of the codifferential can be described by an explicit multiplication map, allowing an easy computation of the rank. This rank turns out to be 44. A first-order calculation on an explicit deformation of a cyclic trigonal vanishing theta-null differentiates the global Gaussian-map identity for the regularized conormal bivector. Including the variation of the Gaussian map gives a nonzero first normal symbol. The resulting first-order form is nonzero on the null space of the limiting skew-symmetric matrix, so the rank jumps to 66 on nearby curves, showing that d=4d=4.

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Schottky versus super Schottky in genus 4 — Mathematical Frontier Network