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Erdős Problem #548: the Erdős–Sós conjecture

For every n,kn,k with k+1nk+1\le n, every simple graph GG on nn vertices satisfying E(G)k12n+1 |E(G)|\ge \frac{k-1}{2}n+1 contains every tree on k+1k+1 vertices. The proof counts pairs (π,j)(\pi,j) where π=(v1,,vn)\pi=(v_1,\ldots,v_n) is an ordering of the host vertices and v1vjv_1v_j is an edge. There are exactly 2E(G)(n1)! 2|E(G)|(n-1)! such pairs. An induction on the target tree bounds this quantity by a rooted-copy count plus (k1)n!. (k-1)n!. If the target tree is absent, the rooted-copy term vanishes and one obtains 2E(G)(k1)n, 2|E(G)|\le (k-1)n, contradicting the density hypothesis.

Exact FrontierDelta

Prior state unknownproved

Scope and record

Occurred: Aug 26, 2026

Delta type: SOURCE CLAIM

Assumptions: VibeMathed verification: lean-verified. Publication: announcement. AI contribution: ai-discovered. VibeMathed editorial classifications, scores, notes, relations, and dataset structure are CC BY 4.0. Source statements and linked content retain their own rights.

Canonical aliases: Erdős Problem #548: the Erdős–Sós conjecture · Erdos #548 (Erdős–Sós) · Problem 548

Confidence: Not scored

Registry verification: lean verified · announcement · resolved

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Attribution

VibeMathed
registry · event recorded by

GPT-6 Astra (pre-release)
model · ai model contributor · OpenAI

Tom Adamczewski
human · human collaborator

Artifacts and verifiers

Solution.lean and the Lean development

lean artifact · passed

Artifact ↗
Challenge.lean: the compared statement

formal registration · pending

Artifact ↗

Compute record

No linked compute attempts recorded.

Lineage and corrections

Erdős Problem #548: the Erdős–Sós conjecture parent of this event

For every n,kn,k with k+1nk+1\le n, every simple graph GG on nn vertices satisfying E(G)k12n+1 |E(G)|\ge \frac{k-1}{2}n+1 contains every tree on k+1k+1 vertices. The proof counts pairs (π,j)(\pi,j) where π=(v1,,vn)\pi=(v_1,\ldots,v_n) is an ordering of the host vertices and v1vjv_1v_j is an edge. There are exactly 2E(G)(n1)! 2|E(G)|(n-1)! such pairs. An induction on the target tree bounds this quantity by a rooted-copy count plus (k1)n!. (k-1)n!. If the target tree is absent, the rooted-copy term vanishes and one obtains 2E(G)(k1)n, 2|E(G)|\le (k-1)n, contradicting the density hypothesis. parent of this event

VibeMathed record: Erdős Problem #548: the Erdős–Sós conjecture evidence for this event

Erdős Problem #548: the Erdős–Sós conjecture evidence for this event

erdosproblems.com/548: status and Thomas Bloom's proof exposition evidence for this event

Challenge.lean: the compared statement evidence for this event

Solution.lean and the Lean development evidence for this event

Epoch AI, Announcing FrontierMath Erdős (1 September 2026) evidence for this event

This event attributed to GPT-6 Astra (pre-release)

This event attributed to Tom Adamczewski

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Erdős Problem #548: the Erdős–Sós conjecture — Mathematical Frontier Network