combinatorics / Graph theory

Erdős Problem #548: the Erdős–Sós conjecture

For every n,kn,k with k+1≤nk+1\le n, every simple graph GG on nn vertices satisfying ∣E(G)∣≥k−12n+1 |E(G)|\ge \frac{k-1}{2}n+1 contains every tree on k+1k+1 vertices. The proof counts pairs (π,j)(\pi,j) where π=(v1,…,vn)\pi=(v_1,\ldots,v_n) is an ordering of the host vertices and v1vjv_1v_j is an edge. There are exactly 2∣E(G)∣(n−1)! 2|E(G)|(n-1)! such pairs. An induction on the target tree bounds this quantity by a rooted-copy count plus (k−1)n!. (k-1)n!. If the target tree is absent, the rooted-copy term vanishes and one obtains 2∣E(G)∣≤(k−1)n, 2|E(G)|\le (k-1)n, contradicting the density hypothesis.

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combinatoricsAug 26, 2026Significance 58/100Registry: lean verified

Erdős Problem #548: the Erdős–Sós conjecture

Prior state unknown→proved

For every n,kn,k with k+1≤nk+1\le n, every simple graph GG on nn vertices satisfying ∣E(G)∣≥k−12n+1 |E(G)|\ge \frac{k-1}{2}n+1 contains every tree on k+1k+1 vertices. The proof counts pairs (π,j)(\pi,j) where π=(v1,…,vn)\pi=(v_1,\ldots,v_n) is an ordering of the host vertices and v1vjv_1v_j is an edge. There are exactly 2∣E(G)∣(n−1)! 2|E(G)|(n-1)! such pairs. An induction on the target tree bounds this quantity by a rooted-copy count plus…

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For every n,kn,k with k+1≤nk+1\le n, every simple graph GG on nn vertices satisfying ∣E(G)∣≥k−12n+1 |E(G)|\ge \frac{k-1}{2}n+1 contains every tree on k+1k+1 vertices. The proof counts pairs (π,j)(\pi,j) where π=(v1,…,vn)\pi=(v_1,\ldots,v_n) is an ordering of the host vertices and v1vjv_1v_j is an edge. There are exactly 2∣E(G)∣(n−1)! 2|E(G)|(n-1)! such pairs. An induction on the target tree bounds this quantity by a rooted-copy count plus (k−1)n!. (k-1)n!. If the target tree is absent, the rooted-copy term vanishes and one obtains 2∣E(G)∣≤(k−1)n, 2|E(G)|\le (k-1)n, contradicting the density hypothesis.

For every n,kn,k with k+1≤nk+1\le n, every simple graph GG on nn vertices satisfying ∣E(G)∣≥k−12n+1 |E(G)|\ge \frac{k-1}{2}n+1 contains every tree on k+1k+1 vertices. The proof counts pairs (π,j)(\pi,j) where π=(v1,…,vn)\pi=(v_1,\ldots,v_n) is an ordering of the host vertices and v1vjv_1v_j is an edge. There are exactly 2∣E(G)∣(n−1)! 2|E(G)|(n-1)! such pairs. An induction on the target tree bounds this quantity by a rooted-copy count plus (k−1)n!. (k-1)n!. If the target tree is absent, the rooted-copy term vanishes and one obtains 2∣E(G)∣≤(k−1)n, 2|E(G)|\le (k-1)n, contradicting the density hypothesis.

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Erdős Problem #548: the Erdős–Sós conjecture — Mathematical Frontier Network