combinatorics / Enumerative combinatorics
Is the number of nonnesting permutations of $\{1,1,\dots,n,n\}$ avoiding both $1132$ and $3312$ equal to $3^n - 3 \cdot 2^{n-1} + 1$ for every $n \ge 1$?
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Is the number of nonnesting permutations of $\{1,1,\dots,n,n\}$ avoiding both $1132$ and $3312$ equal to $3^n - 3 \cdot 2^{n-1} + 1$ for every $n \ge 1$?
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Is the number of nonnesting permutations of $\{1,1,\dots,n,n\}$ avoiding both $1132$ and $3312$ equal to $3^n - 3 \cdot 2^{n-1} + 1$ for every $n \ge 1$?
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