geometry-topology / Convex geometry: volume products and polarity

The Mahler conjecture for general (non-symmetric) convex bodies

Theorem 1.1: for every n≥1n\ge1 and every convex body K⊂RnK\subset\mathbb R^n with Santalo point s(K)s(K), ∣K∣ ∣(K−s(K))∘∣≥(n+1)n+1/(n!)2|K|\,|(K-s(K))^\circ|\ge(n+1)^{n+1}/(n!)^2, with equality iff KK is a simplex; no symmetry or boundary regularity is assumed. The proof goes through Klartag's cone and Laplace-transform correspondence, Gaussian-averaged nearest-point projections onto a cone and its dual, and a spectral comparison whose scalar estimates rest on finite rational certificates with a released Python runner. Corollary: the sharp functional inequality ∫e−φ∫e−φ∗≥en\int e^{-\varphi}\int e^{-\varphi^*}\ge e^n for convex φ\varphi, via Fradelizi-Meyer, and an entropy-transport bound under an extra hypothesis. It does not give the symmetric constant 4n/n!4^n/n!, which is a separate entry.

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geometry-topologySep 22, 2026Significance 55/100Registry: lean checked

The Mahler conjecture for general (non-symmetric) convex bodies

Prior state unknown→proved

Theorem 1.1: for every n≥1n\ge1 and every convex body K⊂RnK\subset\mathbb R^n with Santalo point s(K)s(K), ∣K∣ ∣(K−s(K))∘∣≥(n+1)n+1/(n!)2|K|\,|(K-s(K))^\circ|\ge(n+1)^{n+1}/(n!)^2, with equality iff KK is a simplex; no symmetry or boundary regularity is assumed. The proof goes through Klartag's cone and Laplace-transform correspondence, Gaussian-averaged nearest-point projections onto a cone and its dual, and a spectral comparison whose scalar est…

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Theorem 1.1: for every n≥1n\ge1 and every convex body K⊂RnK\subset\mathbb R^n with Santalo point s(K)s(K), ∣K∣ ∣(K−s(K))∘∣≥(n+1)n+1/(n!)2|K|\,|(K-s(K))^\circ|\ge(n+1)^{n+1}/(n!)^2, with equality iff KK is a simplex; no symmetry or boundary regularity is assumed. The proof goes through Klartag's cone and Laplace-transform correspondence, Gaussian-averaged nearest-point projections onto a cone and its dual, and a spectral comparison whose scalar estimates rest on finite rational certificates with a released Python runner. Corollary: the sharp functional inequality ∫e−φ∫e−φ∗≥en\int e^{-\varphi}\int e^{-\varphi^*}\ge e^n for convex φ\varphi, via Fradelizi-Meyer, and an entropy-transport bound under an extra hypothesis. It does not give the symmetric constant 4n/n!4^n/n!, which is a separate entry.

Theorem 1.1: for every n≥1n\ge1 and every convex body K⊂RnK\subset\mathbb R^n with Santalo point s(K)s(K), ∣K∣ ∣(K−s(K))∘∣≥(n+1)n+1/(n!)2|K|\,|(K-s(K))^\circ|\ge(n+1)^{n+1}/(n!)^2, with equality iff KK is a simplex; no symmetry or boundary regularity is assumed. The proof goes through Klartag's cone and Laplace-transform correspondence, Gaussian-averaged nearest-point projections onto a cone and its dual, and a spectral comparison whose scalar estimates rest on finite rational certificates with a released Python runner. Corollary: the sharp functional inequality ∫e−φ∫e−φ∗≥en\int e^{-\varphi}\int e^{-\varphi^*}\ge e^n for convex φ\varphi, via Fradelizi-Meyer, and an entropy-transport bound under an extra hypothesis. It does not give the symmetric constant 4n/n!4^n/n!, which is a separate entry.

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