analysis / Geometric function theory, integral means spectrum

Kraetzer's conjecture on the universal integral means spectrum

Theorem 1.1: there are constants 0<ε<1/40<\varepsilon<1/4 and CC with M−1[f′](r)≤C(1−r)−1/4+εM_{-1}[f'](r)\le C(1-r)^{-1/4+\varepsilon} for every f∈Sf\in\mathcal S and 1/2≤r<11/2\le r<1, so Bb(−1)<1/4=p2/4B_b(-1)<1/4=p^2/4 at p=−1p=-1 and Kraetzer's formula is false. The bound needs no bounded image or boundary regularity. Not shown: the true value of Bb(−1)B_b(-1) or any explicit gap, and nothing about p=1p=1 or the Carleson-Jones question; Brennan's value B(−2)=1B(-2)=1, also predicted by Kraetzer, is proved in the companion (separate entry).

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analysisSep 24, 2026Significance 25/100Registry: lean checked

Kraetzer's conjecture on the universal integral means spectrum

Prior state unknown→disproved

Theorem 1.1: there are constants 0<ε<1/40<\varepsilon<1/4 and CC with M−1[f′](r)≤C(1−r)−1/4+εM_{-1}[f'](r)\le C(1-r)^{-1/4+\varepsilon} for every f∈Sf\in\mathcal S and 1/2≤r<11/2\le r<1, so Bb(−1)<1/4=p2/4B_b(-1)<1/4=p^2/4 at p=−1p=-1 and Kraetzer's formula is false. The bound needs no bounded image or boundary regularity. Not shown: the true value of Bb(−1)B_b(-1) or any explicit gap, and nothing about p=1p=1 or the Carleson-Jones question; Brennan's value…

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Theorem 1.1: there are constants 0<ε<1/40<\varepsilon<1/4 and CC with M−1[f′](r)≤C(1−r)−1/4+εM_{-1}[f'](r)\le C(1-r)^{-1/4+\varepsilon} for every f∈Sf\in\mathcal S and 1/2≤r<11/2\le r<1, so Bb(−1)<1/4=p2/4B_b(-1)<1/4=p^2/4 at p=−1p=-1 and Kraetzer's formula is false. The bound needs no bounded image or boundary regularity. Not shown: the true value of Bb(−1)B_b(-1) or any explicit gap, and nothing about p=1p=1 or the Carleson-Jones question; Brennan's value B(−2)=1B(-2)=1, also predicted by Kraetzer, is proved in the companion (separate entry).

Theorem 1.1: there are constants 0<ε<1/40<\varepsilon<1/4 and CC with M−1[f′](r)≤C(1−r)−1/4+εM_{-1}[f'](r)\le C(1-r)^{-1/4+\varepsilon} for every f∈Sf\in\mathcal S and 1/2≤r<11/2\le r<1, so Bb(−1)<1/4=p2/4B_b(-1)<1/4=p^2/4 at p=−1p=-1 and Kraetzer's formula is false. The bound needs no bounded image or boundary regularity. Not shown: the true value of Bb(−1)B_b(-1) or any explicit gap, and nothing about p=1p=1 or the Carleson-Jones question; Brennan's value B(−2)=1B(-2)=1, also predicted by Kraetzer, is proved in the companion (separate entry).

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