combinatorics / Social Choice, Tournaments

Tournaments Determined by Three and Five Voters

Around the Kemeny median problem, which stays open for $m=3$ and $m=5$ voters, the paper refutes three conjectures on tournament inducibility: both conjectures of Milosz, Hamel and Pierrot (the 3-cycle extension for odd $m\ge5$, and $\mathrm{FAS}=\mathrm{HS}_3$ at $n=11$), and Shepard's threshold conjecture.

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combinatoricsJul 29, 2026Significance 10/100Registry: unreviewed

Tournaments Determined by Three and Five Voters

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Around the Kemeny median problem, which stays open for $m=3$ and $m=5$ voters, the paper refutes three conjectures on tournament inducibility: both conjectures of Milosz, Hamel and Pierrot (the 3-cycle extension for odd $m\ge5$, and $\mathrm{FAS}=\mathrm{HS}_3$ at $n=11$), and Shepard's threshold conjecture.

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Around the Kemeny median problem, which stays open for $m=3$ and $m=5$ voters, the paper refutes three conjectures on tournament inducibility: both conjectures of Milosz, Hamel and Pierrot (the 3-cycle extension for odd $m\ge5$, and $\mathrm{FAS}=\mathrm{HS}_3$ at $n=11$), and Shepard's threshold conjecture.

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Tournaments Determined by Three and Five Voters — Mathematical Frontier Network