Randomized versus quantum query complexity of total Boolean functions: is R(f) = O(Q(f)^3)?
Theorem 1.1: for each fixed k≥2 there are total Boolean functions Fk,m with Q(Fk,m)≤Ckm(logm)bk and R(Fk,m)≥ckm2−1/k/(logm)2, a power 4−2/k separation up to logarithms, so no bound R=O((1+Q)α) holds with α<4. With the known R=O(Q4) the optimal exponent is exactly 4, and the cubic conjecture is false. The functions are cheat-sheet-style columns whose certificate cells are addressed by answers to partial-function instances. Not shown: a separation with exponent exactly 4 for a single family, or new results for partial functions.
Theorem 1.1: for each fixed k≥2 there are total Boolean functions Fk,m with Q(Fk,m)≤Ckm(logm)bk and R(Fk,m)≥ckm2−1/k/(logm)2, a power 4−2/k separation up to logarithms, so no bound R=O((1+Q)α) holds with α<4. With the known R=O(Q4) the optimal exponent is exactly 4, and the cubic conjecture is false. The functions are cheat-sheet-style columns whose ce…
Theorem 1.1: for each fixed k≥2 there are total Boolean functions Fk,m with Q(Fk,m)≤Ckm(logm)bk and R(Fk,m)≥ckm2−1/k/(logm)2, a power 4−2/k separation up to logarithms, so no bound R=O((1+Q)α) holds with α<4. With the known R=O(Q4) the optimal exponent is exactly 4, and the cubic conjecture is false. The functions are cheat-sheet-style columns whose certificate cells are addressed by answers to partial-function instances. Not shown: a separation with exponent exactly 4 for a single family, or new results for partial functions.
Theorem 1.1: for each fixed k≥2 there are total Boolean functions Fk,m with Q(Fk,m)≤Ckm(logm)bk and R(Fk,m)≥ckm2−1/k/(logm)2, a power 4−2/k separation up to logarithms, so no bound R=O((1+Q)α) holds with α<4. With the known R=O(Q4) the optimal exponent is exactly 4, and the cubic conjecture is false. The functions are cheat-sheet-style columns whose certificate cells are addressed by answers to partial-function instances. Not shown: a separation with exponent exactly 4 for a single family, or new results for partial functions.